A length of roles placed on the floor in the shape of an equilateral triangle of side 2.2 m .If this rope is spread out and a circle is formed out of it , what will be radius of the circle
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Perimeter of equilateral triangle = 2.2+2.2+2.2 = 6.6m
Circumference of circle = perimeter of triangle = 6.6m
2*(22/7)*r = 6.6
r = (6.6*7)/(22*2) = 1.05m
Circumference of circle = perimeter of triangle = 6.6m
2*(22/7)*r = 6.6
r = (6.6*7)/(22*2) = 1.05m
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perimeter of the triangle=circumference of the circle
6•6=2πr
6•6=2*22/7*r
6•6*7/22=2r
0•6*7/2*2=r
r=4•2/2*2
r=2•1/2=1.05m
1•05m is the radius of the circle formed
thanks for the question
6•6=2πr
6•6=2*22/7*r
6•6*7/22=2r
0•6*7/2*2=r
r=4•2/2*2
r=2•1/2=1.05m
1•05m is the radius of the circle formed
thanks for the question
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