a length of verandah is 3cm more than its breath.the numerical value of its atea is equal the numerical value of its perimeier.find the length of verandah
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L = 3 +B
and L×B = 2(L+B)
⇒(3+B)×B = 2[3+B +B] = 2(3+2B)
⇒B²+3B = 6 +4B
⇒B²- B -6 =0
⇒B²-3B +2B -6 =0
⇒B(B-3) + 2(B-3) =0
⇒(B-3)(B+2)=0
∴B = 3 cm since value cannot be negative
so length = 3+3 = 6 cm
and L×B = 2(L+B)
⇒(3+B)×B = 2[3+B +B] = 2(3+2B)
⇒B²+3B = 6 +4B
⇒B²- B -6 =0
⇒B²-3B +2B -6 =0
⇒B(B-3) + 2(B-3) =0
⇒(B-3)(B+2)=0
∴B = 3 cm since value cannot be negative
so length = 3+3 = 6 cm
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