A lens forms a sharp image on a screen. On inserting a parallel sided glass slab between the lens and the screen, it is found necessary to move the screen a distance 'd' away the lens in order to focus the image to be sharp again. If the refractive index of glass relative to air is u, the thickness of the glass slab is
Answers
Explanation:
When a glass slab of thickness t is inserted in the path of the light rays, the point of intersection of ray shifts by t(1−
μ
1
) in the direction in which the ray is moving.
As per the question d=t(1−
μ
1
)
Solving we get, t=
(μ−1)
dμ
Answer:
A lens form a sharp image on a screen. On inserting a parallel-sides slab of glass between the lens and the screen it is found necessary to move the screen a distance d away from the lens in order for the image to be again sharply focused. If the refractive index of glass relative to air is μ, then the thickness of the slab is
Explanation:
ANSWER
When a glass slab of thickness t is inserted in the path of the light rays, the point of intersection of ray shifts by t(1−
μ
1
) in the direction in which the ray is moving.
As per the question d=t(1−
μ
1
)
Solving we get, t=
(μ−1)
dμ