a lens has power +2d . find the focal length and nature of the lens . an object is placed at a distance of 10 cm from this lens . where will the image be formed and what will be it's nature.
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Power = 2d
Focal length = 1/p
= 1/2 m = 100/2 cm
The lens is convex lens as focal length is positive
If u = -10 cm
f = 50 cm
1/f = 1/v - 1/u
1/50 = 1/v - 1/(-10)
1/50 = 1/v + 1/10
1/50 - 1/10 = 1/v
(1 - 5)/50 = 1/v
1/v = -4/50
v = -50/4 cm
As v is negative the image will form on the same side of object so nature of image is virtual and erect.
Hope it works :)
Focal length = 1/p
= 1/2 m = 100/2 cm
The lens is convex lens as focal length is positive
If u = -10 cm
f = 50 cm
1/f = 1/v - 1/u
1/50 = 1/v - 1/(-10)
1/50 = 1/v + 1/10
1/50 - 1/10 = 1/v
(1 - 5)/50 = 1/v
1/v = -4/50
v = -50/4 cm
As v is negative the image will form on the same side of object so nature of image is virtual and erect.
Hope it works :)
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a lens has power +2d . find the focal length and nature of the lens . an object is placed at a distance of 10 cm from this lens . where will the image be formed and what will be it's nature. is in image
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