A lens of focal length 12cm produces an erect image three times the size of object. What is the distance between object and image?
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1
Magnification , m=
u
v
3=
u
v
⇒v=3u
Lens formula :
v
1
−
u
1
=
f
1
3u
1
−
u
1
=
12
1
3u
−2
=
12
1
⇒u=−8cm
v=3×−8=−24cm
Distance between object and image =u−v=−8−(−24)=−8+24=16cm
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