A lens of focal length 20 cm forms an erect image of magnification 0.5. Find
the nature of lens and position of object.
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Explan 16 cm. Magnification, m = v/u. 3 = v/u. ⇒ v = 3u. Lens formula : 1/v – 1/u = 1/f. 1/3u = 1/u = 1/12. -2/3u = 1/12. ⇒ u = -8 cm. V = 3 × (-8) = -24. Distance ...ation:
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