A lens of focal length 20cm is used to produce ten times magnified image of film slide on a screen .how far must the slide be placed from the lens.
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Answered by
22
☆☆ranshsangwan☆☆
We have,
f = 20 cm
Object distance = -u
Image distance = v
Magnification, m = -10 (negative sign implies real image)
Now, v/(-u) = -10
=> v = 10u
Using,
1/f = 1/v – 1/u
=> 1/20 = 1/10u + 1/u
=> u = 22 cm
Thus, object distance is = -u = -22 cm
So, the slide is placed at a distance 22 cm from the pole of the lens
We have,
f = 20 cm
Object distance = -u
Image distance = v
Magnification, m = -10 (negative sign implies real image)
Now, v/(-u) = -10
=> v = 10u
Using,
1/f = 1/v – 1/u
=> 1/20 = 1/10u + 1/u
=> u = 22 cm
Thus, object distance is = -u = -22 cm
So, the slide is placed at a distance 22 cm from the pole of the lens
Answered by
3
Thus it is
F = 20 cm
Thus by magnification
10 = v / u
So if lens then
1/v -10/v = 1/20
V = -180 cm
F = 20 cm
Thus by magnification
10 = v / u
So if lens then
1/v -10/v = 1/20
V = -180 cm
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