A lens of focal length 5 cm is being used by student in the laboratory as a magnifying glass. His least distance of distinct vision is 25 cm. What magnification is the student getting?
Answers
Answered by
50
Heyy mate ❤✌✌❤
Here's your Answer.....
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Focal Length= 5cm.
U = -25 cm
By Lens Formula,
1/v - 1/u = 1/f
=> 1/v = 1/5 - 1/25
=> 1/v =4/25.
Therefore, v= 25/4.
Now, Magnification = V/U
=> M = (25/4)/(-25)
=> M. =-1/4
=> M = -0.25.
✔✔✔
Here's your Answer.....
⤵️⤵️⤵️⤵️⤵️⤵️⤵️
Focal Length= 5cm.
U = -25 cm
By Lens Formula,
1/v - 1/u = 1/f
=> 1/v = 1/5 - 1/25
=> 1/v =4/25.
Therefore, v= 25/4.
Now, Magnification = V/U
=> M = (25/4)/(-25)
=> M. =-1/4
=> M = -0.25.
✔✔✔
Answered by
15
M=1+D/f
=1+25/5
=1+5
=6
Therefore, Ans. 6X....
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