Question

A lens of focal length 5cm is being used by a student in the laboratory as a magnifying glass. His least distance of distinct vision is 25cm. What magnification is the student getting?

Answer 1

Answer:

Hey mate✌️✌️

Here is ur answer.......

focal length (f)= 5cm

distance (u)= -25cm

( 'u' is always minus in lens and mirror).

By lens formula,

1/v - 1/u = 1/f

1/v= 1/f + 1/u

1/v= 1/5 - 1/25

1/v= 4/25

Therefore,

v = 25/4

Now magnification= v/u

m=v/u

m= (25/4)/(-25)

m= -1/4

m= -0.25

Hope this helps u mate✌️✌️

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