A lens produces a magnification of -0.5 . Is this a converging or diverging the lens? If the focal length of the lens is 6cm, diagram showing the image formation in the case?
answer:- f=+30cm (convex lens)
v=+60cm (since image forms on the other side of lens)
= 1/f=1/v-1/u
= 1/I =1/60-1/30
=1-2/60
=-1/60
u=-60cm
m=image distance(v)/object distance(u)
m=60cm/-60cm
m=-1cm
Answers
Answered by
2
Answer:
According to the question;
Object distance (u) = -60cm;
Image distance (v) = 120cm;
Focal length = f
By lens formula;
⇒ f = 40cm.
Therefore Focal length of lens is 40 cm.
Since the focal length is positive. Therefore the lens is convex lens of focal length 40cm.
Now;
Height of object h1= 5cm;
Magnification =
=
Putting values of v and u
Magnification =
⇒
⇒ h2 = -2 × 5= -10 cm
Height of image is 10 cm.
Answered by
2
Answer:
10 cm hope it help u
@Bblegend
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