Question

A lens produces a magnification of-0.5. Is this a converging or diverging lens? If the focal length of the lens is 6cm, draw a ray diagram showing the image formation in this case.​

Answer 1

Answer:

maginification is negative ,therefore image formed is real and inverted. Real and in verted image are always formed in convex or converging lens.

f=6cm

$\frac{1}{f} = \frac{1}{v} - \frac{1}{u} \\ \frac{1}{u} = \frac{f - v}{fv} \\ multiply \: by \: v \: on \: both \: sides \\ \frac{v}{u} = \frac{f - v}{f} \\ m = \frac{v}{u} = \frac{f - v}{f} \\ - 0.5 = \frac{6 - v}{6} \\ - 3 = 6 - v \\ v = 9cm$

Hope it helps you...