Question

A lens which has focal length of 4 cm and refractive index of 1.4 is immersed in a liquid of refractive index 1.6, then find its focal

Answer 1

we can use the lens makers formula to solve this problem. Lens makers formula is 1/f=(n−1)(1/R1–1/R2)1/f=(n−1)(1/R1–1/R2). Substituting the given values, the formula becomes

For the medium of refractive index 1.5

1/15=(1.5–1)(1/R1–1R2)1/15=(1.5–1)(1/R1–1R2) ————(1)

For the medium of refractive index 4/3

1/f=(1.33–1)(1/R1–1/R2)1/f=(1.33–1)(1/R1–1/R2)————(2)

Dividing (1) by (2) will yield the value of f 22.72cm.

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