(a) Let R and S be the sets defined as follows:
R = {x ∈ Z | x is divisible by 2}, S = {y ∈ Z | y is divisible by 3}, then R ∩ S = φ
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Let R and S be the sets defined as follows: R = {x ∈ Z | x is divisible by 2} S = {y ∈ Z | y is divisible by 3} then, R ∩ S = φ
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False Since 6 is divisible by both 3 and 2. Thus,
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