Question

A letter A consists of a uniform wire of resistance 1 ohm per cm. The sides of the letter are each 20 cm long and the cross-piece in the middle is 10 cm long while the apex angle is. Find the resistance of the letter between the two ends of the legs.​

Answer 1

Explanation:

The sides of the letter are 6cm each and the cross piece in middle is ... Calculate the resistance between the ends of the legs. ... The equivalent resistance between two legs is 72/5 ohm.

Answer 2

Let us solve the total resistance for this given "A"Letter

Explanation:

It is given that :

Resistance per centimeter=1 ohm

Apex angle =60 degree (this is given just for confusing otherwise nothing to  do with this value in numerical)

By using this data the diagram is constructed a shown in figure that is attached .

Now , the total resistance in the upper part ;

R1 and R2 is in series .

Therefore :

R=R1+R2

R'=10 +10=20 ohm

Now R' and R3 are parallel , therefore

$1/R"=1/R'+1/R3\\1/R"=1/20 + 1/10\\1/R"=3/20\\R"=20/3 ohm$

Now , R4, R" and R5 are in series therefore , total R of circuit is :

$R=R4+R"+R5\\R=10+20/3+10\\R=80/3 ohm \\R=26.6 ohm$