A letter a is constructed of a unit ohm wire of resistance 1 ohm/cm. the sides of the letter are 20 cm long and cross side is 10 cm long while the apex angle
Answers
Answered by
2
Hi.
R2 + R3 are in series. The calculation for this combination is (R2+R3) = 20 Ohms. In effect we have a single 20 Ohm resistor which we’ll call R23.
R 23 is in parallel with R4. The calculation for this combination is (R23xR4)/R23+R4) = (20 x 10)/(20+10) = 200/30 = 6.66 (recurring). Call it 6.67. So the middle combination of R2, R3, R4 = 6.67 Ohms.
This is in series with R1 and R5 so the total resistance is 10 + 6.67 + 10 Ohms = 26.67 ohm..
Hope this helps u!!
R2 + R3 are in series. The calculation for this combination is (R2+R3) = 20 Ohms. In effect we have a single 20 Ohm resistor which we’ll call R23.
R 23 is in parallel with R4. The calculation for this combination is (R23xR4)/R23+R4) = (20 x 10)/(20+10) = 200/30 = 6.66 (recurring). Call it 6.67. So the middle combination of R2, R3, R4 = 6.67 Ohms.
This is in series with R1 and R5 so the total resistance is 10 + 6.67 + 10 Ohms = 26.67 ohm..
Hope this helps u!!
Attachments:
Similar questions