Question

a letter is chosen at random from letters of the word experiment find the probability of getting vo
wel ,letter E ,
a consonant​

Answer 1

Step-by-step explanation:

(i) Let 'A' = probability that the chosen letter is a vowel

n(A) = a,e,i,o,u = 5

n(S) = total outcomes = 26

therefore, P(A) = $\frac{n(A)}{n(S)}$

P(A) = $\frac{5}{26}$

(ii) Let 'B' = probability that the chosen letter is E

n(B) = E = 1

n(S) = 26

therefore, P(B) = $\frac{n(B)}{n(S)}$

P(B) = $\frac{1}{26}$

(iii) Let 'C' = probability that the chosen letter is a consonant

n(C) = 26 letters of the alphabet - vowels = 26 - 5

n(C) = 21

n(S) = 26

therefore, P(C) = $\frac{n(C)}{n(S)}$

P(B) = $\frac{21}{26}$  

Hope it helps :)

Have a good day.