Question

A letter is chosen at random from the word mathematics : find the probability of getting the letter M and E

Answer 1

Answer:

Total no. of outcomes P(a) = 11

No. of favourable outcomes P(E) = 3

probability of getting M or E = no. of favourable outcome/ total outcomes

=P(E)/P(a)

=3/11

Answer 2

MATHEMATICS

the word mathematics contains 11 letters . in which letter M and A comes twice.

To find :-

the probability of getting the letter M and E choosing randomly from word mathematics.

we know :-

$\sf \: P(E) \: = \dfrac{number \: of \: favorable \:outcomes }{number \: of \: all \: possible \: outcomes}$

total number of possible outcomes = 11

$\therefore \sf \: probability \: of \: getting \: M \: = \dfrac{2}{11} \\ \\ \sf \: probability \: of \: getting \: A\: = \frac{1}{11}$

there are 2 letter of M that's why favourable outcomes is 2 .