Question

A letter is chosen from the word 'RECTANGLE'. What is the probability that it is
(1
) a consonant (ii) not a consonant.​

Answer 1

Answer:

If we take "at random" to mean uniformly at random (which is the typical interpretation when there is no other information given) then the answer is actually FIVE out of eleven (not 4 out of eleven as the other answers give).

If we take "at random" to mean uniformly at random (which is the typical interpretation when there is no other information given) then the answer is actually FIVE out of eleven (not 4 out of eleven as the other answers give).In English, the letter Y is considered a vowel when it makes the sound of a long E as it does in the word PROBABILITY. So the vowels are the A, the two I's, the O, and the Y -- a total of five of the eleven letters.

If we take "at random" to mean uniformly at random (which is the typical interpretation when there is no other information given) then the answer is actually FIVE out of eleven (not 4 out of eleven as the other answers give).In English, the letter Y is considered a vowel when it makes the sound of a long E as it does in the word PROBABILITY. So the vowels are the A, the two I's, the O, and the Y -- a total of five of the eleven letters.The only thing I have to add is that while "at random" is usually taken to mean uniformly at random, it need not mean this. For example, we could assign the probabilities in such a way that each letter is twice as likely as the letter before it. So "p" would have probability 1/2047 of being selected, "r" would have probability 2/2047, "o" would have probability 4/2047, and so on. Finally "y" would have probability 1024/2047. In this case, we'd add the probabilities of the five vowels to get a total probability of 1346/2047.

Answer 2

Answer:

RECTANGEL

Total no = 9

and consonant is 6

so your answer will be 6 /9

(a) is correct option