Math, asked by redent9295, 11 months ago

A letter lock consists of 4 rings, each ring contains 9 non-zero digits. This lock can be opened by setting a 4 digit code with the proper combination of each of the 4 rings. Maximum how many codes can be formed to open the lock?

Answers

Answered by eudora

0

There are 6561 codes can be formed to open the lock.

Step-by-step explanation:

A letter lock consists of 4 rings. Each ring contains 9 non-zero digits.

We can say in other words each ring contains 9 numbers.

Each ring has 9 options to get right number. Each digit can be arrange at different position in 9 different ways.

Therefore, maximum ways of codes = 9 × 9 × 9 × 9

= 9⁴

= 6561 ways

There are 6561 codes can be formed to open the lock.

Learn more question related combination : https://brainly.in/question/14771457

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