Question

A Lever
of 120cm has an effort of 15 kgf at
а a distande
of 30 an from the fulcrum at one
end what load can be applied at the other and ?

Answer 1

Answer:

A Lever of 120cm has an effort of 15 kgf at a distance of 30 cm from the fulcrum at one end. The load applied at the other end will be $3.75\ kgf$  

Explanation:

The mechanical advantage is defined as the ratio of load and effort. It is given by the expression,

Mechanical advantage,   $M. A= \frac{Load}{Effort}$   ...(1)

It is also can be expressed in terms of load arm and effort arm as,

$M.A = \frac{Effort\ arm}{Load\ arm}$    ...(2)

In the question, it is given that,

Effort arm  $= 30\ cm$

Effort         $=15\ kgf$

Load arm  = $120\ cm$

Using equation (2),

$M.A = \frac{30}{120} = \frac{1}{4}= 0.25$

Then equation (1) becomes,

${Load}= M. A\times Effort$

After substituting values we get,

$load = 0.25\times 15= 3.75 \ kgf$