Question

A lever of a length is 100cm has its fulcrum at a distance of 40cm from the load what is the mechanical advantage of the lever

Answer 1

So as lever= 100 cm

effort arm= 40 cm

load arm= 60 cm

effort=15kg

lever law

load \div effort \: \\ = \: effort \: arm \: \div load \: arm

so here x/15=40/60

that is:; 10/15=40/60

how: 15*4= 60

. so x*4=40

. now x= 40/4=10kg

solved

Answer 2

Answer:

1.5

Explanation:

Length of lever=100 cm

Load arm=40cm

Effort arm=100-40

=60 cm

MA of the lever=Effort arm

Load arm

So, MA of the lever= 60

40

=3 × 100%

2

=150%÷100

=1.5 Answer

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