A lever of length 1 m has a load of 25kgf at a distance of 20cm from one end and the fulcrum is at the end of the shorter arm. The effort is applied at the end of the longer arm. Find its mechanical advantage.
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Answer:
5kgf
Explanation:
We are given
E = 25kgf
Load arm = 100cm
Effort arm = 20cm
Mechanical advantage =
Effort arm/Load arm=100/20=0.2
By definition,
Mechanical advantage =
load/effort=0.2=load/effort
Load = Effort x Mechanical advantage
Load = 25kgf x 0.2
Load = 5kgf
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