Question

a lever of length 100 cm as effort of 30 kgf at the distance of 80 cm from the fulcrum at one end . what load can be applied on it's another end​

Answer 1

Answer:

We are given

E = 15kgf

Load arm = 100cm

Effort arm = 40cm

Mechanical advantage =

\frac{Effort\ arm}{Load\ arm}=\frac{40}{100}=0.4

By definition,

Mechanical advantage =

\frac{Load}{Effort}

= 0.4 = \frac{Load}{Effort}

Load = Effort x Mechanical advantage

Load = 15kgf x 0.4

Load = 6kgf