a lever of length 100 CM has a effort of 15 kgf at a distance of 40 CM from the fulcrum at one end what load can be applied as it's other end
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The answer is 6. I hope this helps and please mark it as brainliest......
Explanation:
Length of lever = 100 cm
Effort applied = 15 kgf
Effort arm = 40 cm
Load applied = l
load arm = length of lever
= 100 cm
Load x Load Arm = Effort x Effort Arm
=> l x 100 cm = 15 kgf x 40 cm
=> 100 l = 600
=> l =
=> l = 6
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