Question

A lever of length 100 cm has effort of 15 kgf at a
distance of 40 cm from the fulcrum at one end,
What load can be applied at its other end ?
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Answer 1

Answer:

This is your answer.

hope this is help full

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Answer 2

Answer:

The answer is 6. I hope this helps and please mark it as brainliest......

Explanation:

Length of lever = 100 cm

Effort applied = 15 kgf

Effort arm = 40 cm

Load applied = l

load arm = length of lever

               = 100 cm

Load x Load Arm = Effort x Effort Arm

=> l x 100 cm  = 15 kgf  x 40  cm

=> 100 l = 600

=> l = $\frac{600}{100}$

=> l = 6