Question

A lever of length 100 cm has effort of 15 kgf at a
distance of 40 cm from the fulcrum at one end.
What load can be applied at its other end ?​

Answer 1

Answer:

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Step-by-step explanation:

We are given

E = 15kgf

Load arm = 100cm

Effort arm = 40cm

$mechanical \: advantage \: = \frac{100}{40} = 0.4$

Load = Effort x Mechanical advant Load = 15kgf x 0.4

Load = 6kgf