Question

A lever of length 150cm has effort of 20 kgf at a distance of 45 cm from the fulcrum at one end. What load can be applied at its other end?​

Answer 1

Answer:

Given:-

Effort = 20kgf

Load arm = 150 cm

Effort arm = 45 cm

Mechanical advantage

»» Effort arm/Load arm

»» 45/150 = 0.3

Using Definition:-

Mechanical advantage = Load/Effort

Therefore,

0.3 = Load/20kgf

»» Load = 20kgf × 0.3

»» Load = 6kgf

Final answer:-

6kgf load can be applied at its other end.