Question

A lever of length 200cm has a load of 20kgf at a distance of 40cm from one end and fulcrum is at the end of shorter arm. The effort is applied at the end of longer arm.

Answer 1

Answer:

6

Selina solutions

Grade 6

Biology

Mathematics

Physics

Chapters in CONCISE Physics - Middle School - 6

Exercises in Simple Machines

Question 4

Q4) A lever of length 100 cm has effort of 15 kgf at a distance of 40 cm from the fulcrum at one end. What load can be applied at its other end?

Solution:

We are given

E = 15kgf

Load arm = 100cm

Effort arm = 40cm

Mechanical advantage =

\frac{Effort\ arm}{Load\ arm}=\frac{40}{100}=0.4

Load arm

Effort arm

=

100

40

=0.4

By definition,

Mechanical advantage =

\frac{Load}{Effort}

Effort

Load

= 0.4 = \frac{Load}{Effort}

Effort

Load

Load = Effort x Mechanical advantage

Load = 15kgf x 0.4

Load = 6kgf