. A library charges Rs.20 for the first 3 days and Rs.12 per each subsequent day. Write a linear equation
depicting the relation between x and y and draw the graph.
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Let the fixed charge for 3 days =x and additional charge =y
According to the question
⇒x+4y=27....eq1
⇒x+2y=21....eq2
Subtract eq1 and eq2
⇒(3x+4y=27)−(3x+2y=21)⇒2y=6⇒y=3
put y=3 in eq1
⇒x+4×3=27⇒x=15
Fixed charges = Rs. 15
The charge for each extra day = Rs. 3
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