Question

A library has a copies of one book, b copies of each of
two books, c copies of each of three books, and single
copies of d books. The total number of ways in which
these books can be distributed is
(a + b + c + d)!
(a + 2b +30 +d)!
a! b! c!
a! (b!)? (c!)
(a +2b + 3c+d)!
(d) none of these
a! b! !​

Answer 1

Answer:

a+2b + 3c +d is ur answer.

hope this will help u

Answer 2

Answer:

Step-by-step explanation:

Total no. of books = a + 2b + 3c + d

No. of distributions = (a + 2b + 3c + d )!/(a!)(b!)^2 (c!)^3 (d!)