Question

A library is 10m long and 8 m wide its floor is required to be covered by tils of 80cm by 50 cm if each tile cost₹42.5 find the total cost of the tiles required.

Answer 1

Number of tiles needed length-wise:

10m = 1000 cm

1000 ÷ 50 = 20 tiles

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Number of tiles needed breadth-wise:

8m = 800 cm

800 ÷ 80 = 10 tiles

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Find Total tiles needed:

20 x 10 = 200 tiles

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Find cost of the tiles:

1 tile = 42.5

200 tiles = 42.5 x 200 = ₹8500

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Answer: ₹8500

Answer 2

area of each tile
$area \: of \: each \: tile \\ = l \times b \\ = 0.8 \times 0.5 \\ = 0.40 {m}^{2} \\ \\ area \: of \: library \\ = l \times b \\ = 10 \times 8 \\ = 80 \\ therefore \: no \: of \: tiles \: = \frac{area \: of \: library}{area \: of \: each \: tile } \\ = \frac{80}{0.40} \\ = \frac{80 \times 100}{0.40 \times 100} \\ = \frac{8000}{40} \\ = 200 \\ therefore \: no \: of \: tiles \: = 200 \\ cost \: of \: each \: tile = 42.5 \\ cost \: for \: entire \: floor = 42.5 \times 200 \\ = 8500$