Question

A lid of a rectangular box of sides 40 cm by 10 cm is sealed all around with tape such that there is an overlapping of 5cm of the tape. what is the length of the tape used?​

Answer 1

Answer:

105 cm

Step-by-step explanation:

So for the this we have to find the perimeter of the lid of that rectangular box, so answer is

Perimeter = 2×(length + breadth), 2×(L+B) in short

Perimeter = 2×(length + breadth), 2×(L+B) in short = 2×(40+10)

Perimeter = 2×(length + breadth), 2×(L+B) in short = 2×(40+10) = 2×50

Perimeter = 2×(length + breadth), 2×(L+B) in short = 2×(40+10) = 2×50 = 100cm

so perimeter is 100cm, but there is a overlapping of 5cm so we have add 5cm to 100cm (5cm+100cm) which is 105cm.

The length of the tape used is equal to 105cm.