Question

A lid of rectangular box of sides 40 cm by 10 cm is sealed all around with tape such that there is an overlapping of 5 cm of the tape. What is the length of the tape used ?


with example​

Answer 1

${\huge{\pink {\mathfrak{soution}}}}$

The total length of tape required = Perimeter of the rectangle.

= 2(lenght+breadth)

= 2(lenght+breadth)= 2(40+10)

= 2(lenght+breadth)= 2(40+10)= 2(50)

= 2(lenght+breadth)= 2(40+10)= 2(50)= 100 cmn

= 2(lenght+breadth)= 2(40+10)= 2(50)= 100 cmn= 1 meter

Therefore, total length of tape required is 100 cm or 1 meter