A life insurance agent found the following data about distribution of ages of 100 policy holders. Calculate the median age. [Policies are given only to persons having age 18 years onwards but less than 60 years.]
Age (in years) Below 20 Below 25 Below 30 Below 35 Below 40 Below 45 Below 50 Below 55 Below 60
Number of policy holders 2 6 24 45 78 89 92 98 100
Answers
Answer:
35.76 years
Step-by-step explanation:
Number of policy holders = n = 100 (Given)
Thus, n/2 = 100/2 = 50
The cumulative frequency greater than 50 is 78 with the corresponding class 35 - 40. Therefore, the median class is 35 - 40.
Thus, l = 35 , f = 33, c.f = 45, h = 5
MEDIAN = l + [(n/2 - cf )/f ] ×h
Where, l is the lower limit of the median class, n is the number of the observations , cf is the cumulative frequency, f is the frequency of the median class and h is the class size
= 35 + [50 - 45)/33] × 5
= 35 + (5 × 5)/33
= 35 + 25/33
= 35.76
Thus, the median age is 35.76 years.
Answer:
Step-by-step explanation:
Step-by-step explanation:
Number of policy holders = n = 100 (Given)
Thus, n/2 = 100/2 = 50
The cumulative frequency greater than 50 is 78 with the corresponding class 35 - 40. Therefore, the median class is 35 - 40.
Thus, l = 35 , f = 33, c.f = 45, h = 5
MEDIAN = l + [(n/2 - cf )/f ] ×h
Where, l is the lower limit of the median class, n is the number of the observations , cf is the cumulative frequency, f is the frequency of the median class and h is the class size
= 35 + [50 - 45)/33] × 5
= 35 + (5 × 5)/33
= 35 + 25/33
= 35.76
Thus, the median age is 35.76 years.