Math, asked by lakes5727, 8 months ago

A life insurance agent found the following data for distribution of ages of 100 policy holders. Calculate the median age, if policies are only given to persons having age 18 years onwards but less than 60 years.
Age in years Number of policy holders
Blow 20 2
Blow 25 6
Blow 30 24
Blow 35 45
Blow 40 78
Blow 45 89
Blow 50 92
Blow 55 98
Blow 60 100

Answers

Answered by AditiHegde
9

The median age, if policies are only given to persons having age 18 years onwards but less than 60 years is 35.76.

Given,

Age in years    Number of policy holders

Blow 20                           2

Blow 25                           6

Blow 30                           24

Blow 35                           45

Blow 40                           78

Blow 45                           89

Blow 50                           92

Blow 55                           98

Blow 60                           100

we have,

Age in years    Number of policy holders (fi)          Cumulative freq (cf)

0 - 20                             2                                               2

20 - 25                           6-2=4                                       2+4=6

25 - 30                           24-6=18                                     6+18=24

30 - 35                           45 -24=21                                 24+21=45

35 - 40                          78 -45=33                                  45+33=78

40 - 45                           89 -78=11                                    78+11=89

45 - 50                          92 -89=3                                    89+3=92

50 - 55                           98-92=6                                   92+6=98

55 - 60                          100-98=2                                  98+2=100

                                 ∑ fi = 100

N = 100

N/2 = 100/2 = 50

The median class is 35 - 40

Median = l + \dfrac{\frac{N}{2} - cf}{f} * h

where,

l = lower limit of median class = 35

h = class interval = 40-35 = 5

cf = cumulative frequency of median class = 45

f = frequency of median class = 33

Median = 35 + ( 50 - 45 )/ 33 * 5

= 35 + 5 / 33 * 5

= 35 + 25 / 33

= 35.76

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