A lift ascends with a constant acceleration of
2 m/s2. A man throws a ball vertically
upward with a velocity of 12 m/s relative to
lift. The ball will come back to man after a
time of __ s. (g = 10 m/s2)
Answers
Answered by
4
Answer:
t=2sec
Explanation:
As it is a non-inertial frame the net acceleration of the particle will be the sum of the acceleration due to gravity and the acceleration of the elevator.
=10+2=12m/s ²
When ball will fall back into his hands the displacement of the particle will be zero with respect to the man
Also initial velocity of coin, u=20 m/s
Using formula for displacement:-
s=ut+ 1/2 at²
0=12t − 1/2 (12t²)
0=12t − 6t²
0=t(12-6t)
0/t=12-6t
0=12-6t
6t=12
t=12/6
t=2seconds
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