Question

A lift ascends with a constant acceleration of
2 m/s2. A man throws a ball vertically
upward with a velocity of 12 m/s relative to
lift. The ball will come back to man after a
time of __ s. (g = 10 m/s2)​

Answer 1

Answer:

t=2sec

Explanation:

As it is a non-inertial frame the net acceleration of the particle will be the sum of the acceleration due to gravity and the acceleration of the elevator.

=10+2=12m/s ²

When ball  will fall back into his hands the displacement of the particle will be zero with respect to the man

Also initial velocity of coin, u=20 m/s

Using formula for displacement:-

s=ut+  1/2 at²

0=12t − 1/2 (12t²)

0=12t − 6t²

0=t(12-6t)

0/t=12-6t

0=12-6t

6t=12  

t=12/6

t=2seconds