A lift has an upward acceleration of 1m/sec^2. Find the pressure exerted by the man of mass 62.5 kg on the floor of the lift . If the lift had a downward acceleration of 1m/sec^2 . Find the pressure exerted by the man
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I don't know darling....
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Answer:
upward acceleration;
F=mg+ma
= (62kg)(9.8m/s^2)+(62kg)(1m?s^2)
=675KN
downward acceleration;
F=mg+ma
=(62kg)(9.8m/s^2)-(62kg)(1m?s^2)
=550KN
Step-by-step explanation:
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