Question

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A lift in a building of height 90 feet with transparent glass walls is descending from
the top of the building. At the top of the building, the angle of depression to a fountain
in the garden is 60°. Two minutes later, the angle of depression reduces to 30°. If the
fountain is 30v3 feet from the entrance of the lift, find the speed of the lift which is
descending
Trigonometry < 259​

Answer 1

Answer:

30 ft/min

Step-by-step explanation:

Tan 60°  = Initial Height of Lift / Distance of Fountain from foot of Lift

=> √3  = Initial Height of Lift / 30 √3

=>  Initial Height of Lift = 90 feet

Tan 30°  = Height of Lift after 2 minutes / Distance of Fountain from foot of Lift

=> 1/√3  = Height of Lift after 2 minutes / 30 √3

=> Height of Lift after 2 minutes= 30 feet

Distance covered by lift in 2 Minutes = 90 - 30 = 60 feet

Speed of Lift = 60/2 = 30 ft/min

Answer 2

Answer:

Step-by-step explanation: