A lift in a mine moves down 24 metre in 8 minutes. If it moves in an uniform rate, let's find at what distance below the surface, it will be after 6 minutes. If the lift starts from a height of 10 metre above the ground. let's find how deep the lift will go from the surface after 70 minutes.
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Answer:
Step-by-step explanation:
a) 1 655 m under ground b) 9.31 m under ground
Step-by-step explanation:
V = 24/87 m/min
V = 0.275 m/min
T = 6 min
S = V × T
S = 0.275 × 6
S = 1.655 m
b) same velocity but time is 70 min and lift starts from a height of 10 m above ground
S = V × T
S = 0.275 × 70
S = 19.31
hence we know that the lift starts from a heigt of 10 m from the ground
so. S = 19.31 -10
S = 9.31 m
Hope you will understand the solution provided my me.
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