A lift in which a man is standing, is moving upwards with a
speed of 10 ms⁻¹. The man drops a coin from a height of 4.9
metre and if g = 9.8 ms⁻², then the coin reaches the floor of
the lift after a time
(a) √2 s (b) 1 s
(c)1/2 (d)1/√2
Answers
Answered by
4
Answer:
√2s is your answer
Plz Plz Plz Mark me as BRAINLIEST
Answered by
1
Answer:
Hope it helps.
Please mark me as BRAINLIEST.
Similar questions