Question

A lift is designed to carry a load of 4000 kg through 10
floors of a building, averaging 6 m per floor, in 10 s
Calculate the power of the lift.​

Answer 1

Answer:

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Explanation:

Height

h

=6×10

=60

m (10 floor)

Weight

W=mg

=4000×10=4×104N

Power

P=Whtime=4×104×6010

=24×104Watt

P

=24×104750

=

320hp

Horse Power of lift is

320hp

Answer 2

Answer:

Total distance covered by the lift,

$s = 10 \times 6 = 60m$

time in which this distance is covered,

$t = 10s$

Force exerted by the lift,

F = 4000kg wt = 4000 × 10 N

$= > 4 \times {10}^{4} newton$

POWER OF THE LIFT,

P = FV

$= >( 4 \times {10}^{4} ) \times 6$

$= > 24 \times {10}^{4}$

$240kw$