A lift is down from 70mtr. above the surface and go down to -120mtr below the surface. What is the distance from surface to current position of the lift?.
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How much below the surface of the earth does the acceleration due to gravity become 70% of its value at the surface of earth? (Take R=6400km)
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Let the depth at which acceleration due to gravity(g) becomes 70% or 7g/10 =d
We know that
g
d
=g(1−
R
d
)
Given
g
d
=
10
7g
Also, R=6400km (Radius of earth)
10
7g
=g(1−
6400
d
)
10
7
=1−
6400
d
6400
d
=1−
10
7
6400
d
=
10
3
d=
10
3
×6400
d=1920km
Therefore,
1920km below the surface of earth does the acceleration due to gravity become 70% of its value at the surface of earth.
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