A lift is going upwards with an acceleration 4.9 m/s^2 .What will be the apparent weight of the 60kg man in the lift?What when the lift rises up with a uniform velocity of 4.9 m/s?If the rope of the lift is broken then ?
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Answered by
2
Answer:
F = m(g+a)
= 60 (4.9+9.8)
= 60 (14.7)
= 882 N
Answered by
2
Answer:
The above answer is right answer ❣️
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