Question

a lift is going upwards with an acceleration of 4.9 metre per second square what will be the Apparent weight of a 60 kg man in the left what when the left Rises up with a uniform velocity of 4.9 M per second if the Rope of the lift is broken then

Answer 1

Hello ❤


If the lift is going up with acceleration of 4.9 m/s^2 Then it's apparent weight will be :

» W = m(g+a)


If the rope is broken then acceleration will be equal to acceleration due to gravity then apparent weight will be :

» w = m(g-g) => 0





$= = = = = = = = = = = = = = =$

Answer 2

Answer:

If the lift is going up with acceleration of 4.9 m/s^2 Then it's apparent weight will be :

» W = m(g+a)

If the rope is broken then acceleration will be equal to acceleration due to gravity then apparent weight will be :

» w = m(g-g) => 0

= = = = = = = = = = = = = = ================