A lift is moving down with a retardation of 5m/s.calculate the percentage change in the weight of the person in the lift(g=100m s)
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Dear Student,
Please find below the solution to the asked query:
Moving up:W'=mg+maPercentage change in weight:△WW×100=mamg×100x=100agMoving down:W'=mg−maPercentage change in weight:△WW×100=mamg×100y=100agRatio of x and y:xy=100ag100ag =1:1
Hope this information will clear your doubts about Apparent weight.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
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Please find below the solution to the asked query:
Moving up:W'=mg+maPercentage change in weight:△WW×100=mamg×100x=100agMoving down:W'=mg−maPercentage change in weight:△WW×100=mamg×100y=100agRatio of x and y:xy=100ag100ag =1:1
Hope this information will clear your doubts about Apparent weight.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
plzz mark as brainliest answer
Answered by
0
Answer:
50%
Explanation:
g-A=5-10=5m/s²
So, g-A/g ×100=50%
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