Physics, asked by priyanshutongar, 11 months ago

A lift is moving downwards with acceleration a. A
man in the lift drops a ball within the lift. The
acceleration of the ball as observed by the man in
the lift and a man standing stationary on the ground
are respectively :
(1) g, g
(2) g-a, g-a
(3) g-a, g
(4) a, g

Please answer this question with appropriate explanation​

Answers

Answered by varun1369
9

Hii buddy!

Answer:

Correct answer is g, g-a.

Explanation:

The man in the lift is at rest w. r. t lift, so the acceleration of lift does not affect the acceleration of ball for his reference, so the acceleration of the ball for him would be g.

Whereas for person at the ground will notice the apparent acceleration of the ball, i. e. g - a.

g - a expression comes from the equation mg - ma = ma,

g - a = acceleration.

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