Question

A lift is moving downwards with an acceleration of 1.8 ms. What is apparent weight
realised by a man of mass 5o kg?​

Answer 1

thanks a ton to your pm and I am a huge amount is your answer.

Answer 2

Answer:

Hey mate here is your answer

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400 N.

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Given:

⇒mass:50 kg,

⇒acceleration:1.8 m/s²,

⇒Gravitational acceleration:10 m/s².

To Find:

⇒appareant weight of the man.

Solution:

⇒ here real acceleration is in downward direction so pseudo force acts upward direction,

⇒W app=apparent weigth,

⇒W app=mg-F pseudo,

Calculation:

⇒ W app=(50×10)-(50×1.8),

⇒W app=500-90,

⇒W app is 400 N.

So, the apparent weight of the man is 400 N.

Hope it helps.✔✔✔

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