Question

A lift is moving downwards with an acceleration of 1.8m/s .what is apparent weight realised by a man of mass 50kg

Answer 1

$\underline{ \boxed{ \bold{ \huge{ \purple{Answer}}}}} \\ \\ \star \sf \: \bold{Given} \\ \\ \mapsto \sf \: mass = 50 \: kg \\ \\ \mapsto \sf \: acceleration = 1.8 \: \frac{m}{ {s}^{2} } \: downward \\ \\ \mapsto \sf \: gravitational \: acceleration = 10 \: \frac{m}{ {s}^{2} } \: downward \\ \\ \star \sf \: \bold{To \: Find} \\ \\ \mapsto \sf \: apparent \: weight of \: a \: man \\ \\ \star \sf \: \bold{Formula} \\ \\ \mapsto \sf \: here \: real \: acc. \: is \: in \: downward \: direction \\ \sf \: so \: pseudo \: force \: acts \: in \: upward \: direction. \\ \\ \mapsto \sf \: \boxed{W{ \tiny{app}} = mg - F{ \tiny{pseudo}}} \\ \\ \star \sf \: \bold{Calculation} \\ \\ \mapsto \sf \: W{ \tiny{app}} = (50 \times 10) - (50 \times 1.8) \\ \\ \mapsto \sf \: W{ \tiny{app}} = 500 - 90 = 410 \: N \\ \\ \therefore \boxed{ \sf{ \bold{ \red{W{ \tiny{app}} = 410 \: N}}}}$