Question

a lift is moving downwards with the acceleration of 1.8 m/s what is the apparent weight released by a man of mass of 50N​

Answer 1

a lift is moving downwards with the acceleration of 1.8 m/s what is the apparent weight released by a man of mass of 50N

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Answer 2

Answer:

Given data:

1. acceleration=1.8 ms^-2
2. mass=50 kg
3. g=9.8 ms^-2
4. apparent weight R= ?

Formula:

R=m(g-a)

R=50×(9.8-1.8)

=50×8

=400

R=400 N