A lift is moving upwards with a retardation of 3 m/s2 . A block of mass 5 kg is placed in the lift, the apparent weight of block is ?
Answers
Answered by
10
The acceleration due to gravity with respect to the lift will be = 10-3=7 m/s².
so, apparent weight = 5×7=35N
so, apparent weight = 5×7=35N
Answered by
7
Normal force : N
Acc. to ques , N-mg = ma
N = m(a+g)
Note : acceleration is -ve i.e. -3m/s²
N = 5(-3+9.8) = 34N
Apparent weight = N = 34N
Acc. to ques , N-mg = ma
N = m(a+g)
Note : acceleration is -ve i.e. -3m/s²
N = 5(-3+9.8) = 34N
Apparent weight = N = 34N
Yurashi:
35 N is correct one
That's at g=10m/s² (which I took)
His answer is also correct
for g=9.8m/s²
Hmm
ok...thanks
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